0 votes 0 votes The solution for the differential equation $\dfrac{d^2x}{dt^2}=-9x,$ with initial conditions $x(0)=1$ and $\dfrac{dx}{dt}\bigg \vert_{t=0}=1$ , is $t^2+t+1 \\$ $\sin 3t+\dfrac{1}{3}\cos3t+\dfrac{2}{3} \\$ $\dfrac{1}{3}\sin3t+\cos 3t \\$ $\cos 3t+t$ Differential Equations gate2014-ee-1 differential-equations boundary-limits + – makhdoom ghaya asked Feb 11, 2017 retagged Mar 8, 2021 by Lakshman Bhaiya makhdoom ghaya 9.4k points answer comment Share See all 0 reply Please log in or register to add a comment.