0 votes 0 votes Let $p$ and $q$ be real numbers such that $p^{2}+q^{2}=1$ . The eigenvalues of the matrix $\begin{bmatrix} p & q\\ q& -p \end{bmatrix}$are $1$ and $1$ $1$ and $-1$ $j$ and $-j$ $pq$ and $-pq$ Linear Algebra gateee-2021 linear-algebra matrices eigen-values + – Arjun asked Feb 19, 2021 recategorized Apr 11, 2021 by Lakshman Bhaiya Arjun 15.9k points answer comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes answer -B (1AND-1) SOLUTION FORMULA OF EIGEN VALUE A^2+(diagonal addition)A+(determinant of matrix)=0 where A is eign value diagonal addition (p-p)=0 det(matrix)=(-p^2-q^2) given question (p^2+q^2)=1 then put value A^2-1=0 the A=1and -1(ans) shreekant98 answered Mar 16, 2021 shreekant98 280 points comment Share ask related question See all 0 reply Please log in or register to add a comment.