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The voltage across and the current through a load are expressed as follows

$v(t)=-170 \sin \bigg( 377t- \frac{\pi}{6} \bigg) V$

$i(t) =8 \cos \bigg( 377t + \frac{\pi}{6} \bigg) A$

The average power in watts (round off to one decimal place) consumed by the load is _________.
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