The voltage across and the current through a load are expressed as follows
$v(t)=-170 \sin \bigg( 377t- \frac{\pi}{6} \bigg) V$
$i(t) =8 \cos \bigg( 377t + \frac{\pi}{6} \bigg) A$
The average power in watts (round off to one decimal place) consumed by the load is _________.